Substitueer de hele vierkantswortel of neem dus $$t^2 = \frac{x+1}{x} \Leftrightarrow x = \frac{1}{t^2-1} \Rightarrow \mbox{d}x = \frac{-2t}{(t^2-1)^2}\,\mbox{d}t $$zodat $$\int \frac{x+1}{x} \, \mbox{d}x = \int \frac{-2t^2}{(t^2-1)^2}\,\mbox{d}t$$En nu splitsen; kan je zo verder?