Aanvulling opgave 6

$
\eqalign{
  & y = \sqrt {3 + 4x - x^2 }   \cr
  & y' = \frac{1}
{{2\sqrt {3 + 4x - x^2 } }} \cdot \left( {4 - 2x} \right)  \cr
  & y' = \frac{{2 - x}}
{{\sqrt {3 + 4x - x^2 } }}  \cr
  & y' = \frac{{2 - x}}
{{\sqrt {3 + 4x - x^2 } }}  \cr
  & y' = \frac{{2 - x}}
{y} \cr}
$

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