\require{AMSmath} M. Extra oefeningen a. \eqalign{ f(x) = \frac{{1 - x}} {{\sqrt x }}} b. \eqalign{ f(x) = \frac{{2x - 3}} {{\sqrt {5x + 1} }}} c. \eqalign{f(x) = \frac{{\sqrt {2x + 5} }}{{3x - 1}}} d. \eqalign{f(x) = \frac{{2x + 3}}{{\sqrt {x - 1} }}} e. \eqalign{f(x) = \frac{{\sqrt x - 1}}{{3{x^2} - 4}}} f. \eqalign{f(x) = \left( {2{x^3} - 2} \right) \cdot \sqrt {x + 1}} g. \eqalign{f(x) = \left( {{{x(x - 1)} \over {5 - x}}} \right)^5} Uitwerkingen ©2004-2025 WisFaq
\require{AMSmath}
a. \eqalign{ f(x) = \frac{{1 - x}} {{\sqrt x }}} b. \eqalign{ f(x) = \frac{{2x - 3}} {{\sqrt {5x + 1} }}} c. \eqalign{f(x) = \frac{{\sqrt {2x + 5} }}{{3x - 1}}} d. \eqalign{f(x) = \frac{{2x + 3}}{{\sqrt {x - 1} }}} e. \eqalign{f(x) = \frac{{\sqrt x - 1}}{{3{x^2} - 4}}} f. \eqalign{f(x) = \left( {2{x^3} - 2} \right) \cdot \sqrt {x + 1}} g. \eqalign{f(x) = \left( {{{x(x - 1)} \over {5 - x}}} \right)^5}
b. \eqalign{ f(x) = \frac{{2x - 3}} {{\sqrt {5x + 1} }}}
c. \eqalign{f(x) = \frac{{\sqrt {2x + 5} }}{{3x - 1}}}
d. \eqalign{f(x) = \frac{{2x + 3}}{{\sqrt {x - 1} }}}
e. \eqalign{f(x) = \frac{{\sqrt x - 1}}{{3{x^2} - 4}}}
f. \eqalign{f(x) = \left( {2{x^3} - 2} \right) \cdot \sqrt {x + 1}}
g. \eqalign{f(x) = \left( {{{x(x - 1)} \over {5 - x}}} \right)^5}
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