WisFaq!

Tangens 30°

Volgens mijn cursus is tg 30°=$
\eqalign{\frac{{\sqrt 3 }}
{3}}
$
Maar de Tg is toch sin/cos dus $
\eqalign{{\frac{1}
{2}}}
$ gedeeld door $
\eqalign{\frac{{\sqrt 3 }}
{2}}
$.
Dan bekom ik $
\eqalign{\frac{1}
{{\sqrt 3 }}}
$.
Wat is correct?

heirman gilbert
12-4-2019

Antwoord

Dat gaat zo:

$
\eqalign{
& \sin 30^\circ = \frac{1}
{2} \cr
& \cos 30^\circ = \frac{1}
{2}\sqrt 3 \cr
& \tan 30^\circ = \frac{{\sin 30^\circ }}
{{\cos 30^\circ }} \cr
& \tan 30^\circ = \frac{{\frac{1}
{2}}}
{{\frac{1}
{2}\sqrt 3 }} \cr
& \tan 30^\circ = \frac{1}
{{\sqrt 3 }} \cr
& \tan 30^\circ = \frac{1}
{{\sqrt 3 }} \cdot \frac{{\sqrt 3 }}
{{\sqrt 3 }} \cr
& \tan 30^\circ = \frac{{\sqrt 3 }}
{3} \cr
& \tan 30^\circ = \frac{1}
{3}\sqrt 3 \cr}
$

Helpt dat?

WvR
12-4-2019