$\Large\frac{{5x + 1}}{{x^2 - 1}} = \frac{3}{{x - 1}} + \frac{2}{{x + 1}}$
$\Large\frac{{3 - 5x}}{{x^2 - 4x + 4}} = \frac{{ - 5}}{{x - 2}} + \frac{{ - 7}}{{\left( {x - 2} \right)^2 }}$