\require{AMSmath}

Aanvulling opgave 6

\eqalign{   & y = \sqrt {3 + 4x - x^2 }   \cr   & y' = \frac{1} {{2\sqrt {3 + 4x - x^2 } }} \cdot \left( {4 - 2x} \right)  \cr   & y' = \frac{{2 - x}} {{\sqrt {3 + 4x - x^2 } }}  \cr   & y' = \frac{{2 - x}} {{\sqrt {3 + 4x - x^2 } }}  \cr   & y' = \frac{{2 - x}} {y} \cr}

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